Peak to Peak Voltage Calculator

Peak to Peak Voltage Calculator converts a single AC voltage reading into RMS, peak, average, power, current, and decibel values for accurate waveform, power, and load resistance analysis.

Peak-to-Peak Voltage (VP-P)
28.28 V
The full voltage swing between the positive and negative peaks of the waveform.
Waveform Equivalents
10.00 V (Vrms)
Peak Magnitude (VP) 14.14 V
Absolute Average (Vavg) 9.00 V
Standard alternative voltage metrics translated directly from the AC sinusoidal cycle.
True RMS Power
2.00 W (Real Power)
RMS Current (Irms) 200.00 mA
Load Conductance (G) 20.00 mS
The continuous, effective real power and current delivered to the specified resistive load.
Peak Load Stress
4.00 W (Peak Power)
Peak Current (IP) 282.84 mA
Current Swing (IP-P) 565.69 mA
Maximum instantaneous power and extreme current stresses exerted on the load at the crest of the waveform.
Logarithmic Scales
20.00 dBV (Signal)
Power Level 33.01 dBm
Audio Standard 22.22 dBu
Decibel measurements comparing the RMS voltage and power against standard 1V, 1mW, and 0.775V references.
Model Solved
Analysis successfully computed sine wave parameters, true RMS power, and peak load dynamics based on standard AC sinusoidal equations.

Convert RMS Voltage to Peak-to-Peak, Power, and dB Levels with a Peak to Peak Voltage Calculator for Engineers and Technicians

Electrical engineers, audio technicians, and electronics students use this tool to translate RMS measurements into peak waveform swings, power dissipation, and logarithmic signal levels for AC sinusoidal circuits. Enter your voltage value, select the measurement type, and input load resistance to instantly calculate $V_{P-P}$, true RMS power, peak load stress, and decibel levels.

How to Use

Enter your RMS voltage in volts, select the measurement type, and input load resistance in ohms. The tool returns $V_{P-P}$ in volts, true RMS power in watts, current in milliamps, and decibel levels in dBV, dBm, and dBu.

Formula

Start with the RMS voltage and find the peak voltage for a sine wave:

$$V_P = V_{rms} \times \sqrt{2}$$

Double the peak to get the full swing:

$$V_{P-P} = 2 \times V_P = 2\sqrt{2} \times V_{rms} \approx 2.828 \times V_{rms}$$

Derive average voltage, power, and current:

$$V_{avg} = V_{rms} \times \frac{2\sqrt{2}}{\pi} \approx V_{rms} \times 0.9003$$

$$P_{rms} = \frac{V_{rms}^2}{R}, \quad I_{rms} = \frac{V_{rms}}{R}, \quad G = \frac{1}{R}$$

$$P_{peak} = \frac{V_P^2}{R}, \quad I_P = \frac{V_P}{R}, \quad I_{P-P} = 2 \times I_P$$

Convert to logarithmic scales:

$$dBV = 20 \log_{10}(V_{rms}), \quad dBm = 10 \log_{10}\left(\frac{P_{rms}}{0.001}\right), \quad dBu = 20 \log_{10}\left(\frac{V_{rms}}{0.775}\right)$$

Source: All About Circuits. Common input mistakes: entering peak voltage instead of RMS voltage; applying the $2\sqrt{2}$ factor to non-sinusoidal waveforms; and treating dBm as a voltage reference rather than a 1 mW power reference.

Reference Table

Source$V_{rms}$$V_P$$V_{P-P}$
North American mains120 V169.7 V339.4 V
European mains230 V325.3 V650.5 V
Professional audio (+4 dBu)1.228 V1.736 V3.472 V
Consumer audio (−10 dBV)0.316 V0.447 V0.894 V
Common lab reference10 V14.14 V28.28 V

FAQ

What is the difference between RMS and peak-to-peak voltage?

RMS is the effective heating value of an AC waveform. Peak-to-peak is the total voltage swing from the positive crest to the negative crest. For a sine wave, $V_{P-P} = 2\sqrt{2} \times V_{rms}$.

Can I use this calculator for square or triangle waves?

No. The $2\sqrt{2}$ factor only applies to pure sinusoidal waveforms. Non-sinusoidal waves require different conversion factors based on their duty cycle and shape.

Why does the tool show dBm and dBu separately?

dBm is a power reference to 1 mW, while dBu is a voltage reference to 0.775 V. They are only equal when the load is exactly 600 Ω, which is rare in modern circuits.

What load resistance should I enter?

Use the actual resistance of the circuit or component under analysis. Common values include 50 Ω for RF systems, 8 Ω for speakers, and 600 Ω for legacy audio lines.

Why is peak power twice the RMS power for a sine wave?

Because peak voltage is $\sqrt{2}$ times RMS voltage, and power scales with the square of voltage. Peak power equals $V_{peak}^2/R$, which is exactly twice the RMS power for a pure sine wave.